WebIn a lab, a block weighing 80 N is attached to a springscale, and both are pulled to the right on a horizontalsurface, as shown above. Friction between the block andthe surface is negligible. What is the acceleration of theblock when the scale reads 32 N?(A) 2.0 m/s2 (B) 2.5 m/s2 (C) 4.0 m/s2(D) 6.0 m/s2 (E) 8.0 m/s2 26. WebNov 2, 2006 · A person holds an 80N weight, 2 meters above the floor for 30 seconds, what is the power required in watts to do this? My answer: 4800watts Wg= -mgd Wg= -80N*2m Wg=-160J Wf=-Wg=160J 1watt=1J/s 30*160J/s=4800J/s=4800watts 10. The speed of a 4.0N hockey puck, sliding on the ice surface decreases at the rate of 0.61m/s^2.
Solved In a lab, a block weighing 80 N is attached to a
Web6. To assess the accuracy of a laboratory scale, an object known to weigh exactly 1 gram is weighed n times and the mean scale weight, x, is com-puted. The scale readings are normally distributed with an unknown mean of µ and a standard deviation of σ = 0.01gm. How large should n be so that a 95% confidence interval for µ has a margin of ... WebFeb 17, 2024 · In a lab, a block weighing 80 N is attached to a spring scale, and both are pulled to the right on a horizontal surface, as shown above. Friction between the block and the surface is negligible. What Question 6 In a lab, a block weighing 80 N is attached to a spring scale, and both are pulled to the right on a horizontal surface, as shown above. severe gas in stomach
Unit 2 - Dynamics Problem Set.pdf - AP Physics 1 Unit 2
WebSep 30, 2024 · Solution: The weight of the block W=mg=300\, {\rm N} W = mg = 300N and the magnitude of the external force are given. (a) Again ''constant speed''. If there is a force equal in magnitude but opposite in direction of the external force, then the net force on the object is zero and, as a result, it moves at a constant speed. Webcontribution of electronic balances to local Cub Scout packs for their annual Pinewood Derby events and the supply of scales for use in many school science fairs, including the … WebThe normal force will be equal and opposite to the perpendicular gravity component so N = +mg*cos (Θ). To keep the block from sliding, you would then need to apply a horizontal force equal and opposite to the parallel gravity component so that force would be F = +mg*sin (Θ). Comment ( 6 votes) Upvote Downvote Flag more Show more... Brendan D. the train big boy